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Dated: 29 July 2024
Recently, I came across the following question on Research Gate, posted back in
2015 by Stefano Quattrini:
The wording of the question already suggests a somewhat poor understanding of
what is going on physically in the Doppler effect and this impression is
reinforced by the detailed elaboration of the question, proposing that the
effect is actually due to the energy exchange between the photon and an
absorber, so it should be a consequence of conservation of energy rather than a
matter of frequency evaluation in different frames of reference.
The author seems to be oblivious to the extremely general nature of the Doppler
effect as a wave phenomenon that allows one to assess the question in quite
different contexts than that of electromagnetism. Suppose I am at a beach and
water ripples are rolling towards myself at a frequency of one per second. I can
determine this with a stop watch by counting the crests arriving in a time
interval. Then I run into the sea at the same speed at which the waves are
moving towards me, or even better, there is a footbridge on which I can run
against the wave train without touching the water. At what frequency will I see
the crests now coming towards me? Well, I am running against the wave at a speed
of one wavelength per second and the wave is moving towards me at one wavelength
per second, so I will see two wavelengths of the wave pass under my feet per
second, i.e., I observe a frequency of two crests per second. That is the
Doppler effect! By what energy exchange have I modified the frequency of the
water wave? My only interaction with it is that I see the light coming from it,
hardly a strong enough influence to increase its frequency by a factor of two!
Moreover, my friend has stayed at the beach with his stopwatch and finds that
the frequency of the same ripples that I observe coming to me at 2 Hz is still
one per second for him (as he is not moving towards the wave). By what token
would the 1 Hz be a more real frequency than the 2 Hz or vice versa?
Now, there are of course modifications, when we deal with electromagnetic waves
rather than with water waves, because relativistic aspects will be more
important with the former than with the latter. But, as I show in the following
small essay, these do not significantly change the picture. All that happens is
that time dilation effects have to be added to the regular Doppler effect.
In order to bring out the physics in a transparent way, I derive the effect
first for sound, using geometrical and kinematical aspects of wave propagation,
and show then the minor modifications that are added by relativity. I hope, this
direct kind of approach will be clearer to readers than some more elegant
derivations based on the invariance of the wave phase.
Simple derivation of the Doppler effect,
25.07.2024
What I found a bit shocking is that in the nine years since posting the
question the author has not changed his opinion. Instead he declares the
question solved, but in the wrong sense. That is, he did not seriously try to
understand the physics of the effect (for example by looking at various
derivations or experimental realizations). Rather, he wrote his own paper trying
to prove his view, using energy conservation arguments in the Doppler radar
experiment. Of course, energy and momentum are conserved in that experiment, no
doubt about that. But that does not mean that the Doppler effect is explained by
these conservation laws.
In the Doppler radar case, the effect appears twice, once for the the radar
signal sent out to the object to be detected/measured and a second time for the
reflected ray returning to the sender. The process, to which energy and momentum
conservation arguments are applied, however, is the reflection event, i.e.,
something between the two wave phenomena undergoing a Doppler
effect... One may also describe the reflection as absorption and reemission,
then energy conservation refers to the state of the electromagnetic field plus
the absorber having the same energy before absorption as after reemission. But
this is not the time interval, in which one can locate the two Doppler effects.
Conservation laws should be discussed in a fixed frame of reference, because the
conserved quantities keep their values under the dynamics of the system, not
under a change of frame (energy and momentum both normally change under a change of the
frame of reference). So if we look at energy conservation in the frame of the
sender (of the radar signal) first, we note that the returning signal has a
different frequency from that sent out. (It is usually also much weaker, so its
total energy is smaller than the total energy emitted. But that need not bother
us, we may discuss just the reflected part of the signal or focus on energy
densities instead of total energies.) What this means is simply that the
reflection of the signal did not only lead to a momentum transfer between the
electromagnetic field and the reflector but also to an energy tranfer. The
reflector of course lost the energy that it transmitted to the field (if it
moved towards the sender) or gained the energy that the field transmitted to it
(if it moved away from the sender). However, the (double) Doppler effect is not
caused by energy conservation and energy tranfer to/from the radar field. The
Doppler effect is a phenomenon between frames, energy and momentum conservation
hold in one frame.
There is of course also energy and momentum conservation in the frame of the reflector, and here the incoming frequency is the same as the outgoing frequency, so the energy (per photon) of the incoming and reflected rays are the same, while the momenta are of course changed during reflection. Yet, there is no Doppler effect involved at all in energy conservation at fixed frequency...
Next: Double Doppler effect and conservation laws Up: Introduction science education project Previous: Sagnac effect supporting relativity
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